Designer PDF Viewer

 When you select a contiguous block of text in a PDF viewer, the selection is highlighted with a blue rectangle. In this PDF viewer, each word is highlighted independently. For example:

In this challenge, you will be given a list of letter heights in the alphabet and a string. Using the letter heights given, determine the area of the rectangle highlight in  assuming all letters are  wide.

For example, the highlighted . Assume the heights of the letters are  and . The tallest letter is  high and there are  letters. The hightlighted area will be  so the answer is .

Function Description

Complete the designerPdfViewer function in the editor below. It should return an integer representing the size of the highlighted area.

designerPdfViewer has the following parameter(s):

• h: an array of integers representing the heights of each letter
• word: a string

Input Format

The first line contains  space-separated integers describing the respective heights of each consecutive lowercase English letter, ascii[a-z].
The second line contains a single word, consisting of lowercase English alphabetic letters.

Constraints

• , where  is an English lowercase letter.
•  contains no more than  letters.

Output Format

Print a single integer denoting the area in  of highlighted rectangle when the given word is selected. Do not print units of measure.

Sample Input 0

1 3 1 3 1 4 1 3 2 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5
abc

Sample Output 0

9

Explanation 0

We are highlighting the word abc:

Letter heights are ,  and . The tallest letter, b, is  high. The selection area for this word is .

Note: Recall that the width of each character is .

Sample Input 1

1 3 1 3 1 4 1 3 2 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 7
zaba

Sample Output 1

28

Explanation 1

The tallest letter in  is  at . The selection area for this word is .

Solution:-

import java.io.*;

import java.math.*;

import java.security.*;

import java.text.*;

import java.util.*;

import java.util.concurrent.*;

import java.util.regex.*;

public class Solution {

    // Complete the designerPdfViewer function below.

    static int designerPdfViewer(int[] h, String word) {

        int max=Integer.MIN_VALUE;

        char arr[]=word.toCharArray();

        int ind=0;

        int val[]=new int[word.length()+1];

        for(int i=0;i<word.length();i++)

        {

            val[i]=arr[i]-97;

            System.out.print(val[i]+" ");

        }

        for(int j=0;j<word.length();j++)

        for(int i=0;i<h.length;i++)

        {

            if(val[j]==i)

            if(max<h[i])

            {

                max=h[i];

                ind=i;

            }

        }

        return word.length()*max;

    }

    private static final Scanner scanner = new Scanner(System.in);

    public static void main(String[] args) throws IOException {

        BufferedWriter bufferedWriter = new BufferedWriter(new FileWriter(System.getenv("OUTPUT_PATH")));

        int[] h = new int[26];

        String[] hItems = scanner.nextLine().split(" ");

        scanner.skip("(\r\n|[\n\r\u2028\u2029\u0085])?");

        for (int i = 0; i < 26; i++) {

            int hItem = Integer.parseInt(hItems[i]);

            h[i] = hItem;

        }

        String word = scanner.nextLine();

        int result = designerPdfViewer(h, word);

        bufferedWriter.write(String.valueOf(result));

        bufferedWriter.newLine();

        bufferedWriter.close();

        scanner.close();

    }

}