Left Rotation

 A left rotation operation on an array of size  shifts each of the array's elements  unit to the left. For example, if  left rotations are performed on array , then the array would become .

Given an array of  integers and a number, , perform  left rotations on the array. Then print the updated array as a single line of space-separated integers.

Input Format

The first line contains two space-separated integers denoting the respective values of  (the number of integers) and  (the number of left rotations you must perform).
The second line contains  space-separated integers describing the respective elements of the array's initial state.

Constraints

Output Format

Print a single line of  space-separated integers denoting the final state of the array after performing  left rotations.

Sample Input

5 4
1 2 3 4 5

Sample Output

5 1 2 3 4

Explanation

When we perform  left rotations, the array undergoes the following sequence of changes:

Thus, we print the array's final state as a single line of space-separated values, which is 5 1 2 3 4.

Solution:-

import java.io.*;

import java.math.*;

import java.security.*;

import java.text.*;

import java.util.*;

import java.util.concurrent.*;

import java.util.regex.*;

public class Solution {

    private static final Scanner scanner = new Scanner(System.in);

    public static void main(String[] args) {

        String[] nd = scanner.nextLine().split(" ");

        int n = Integer.parseInt(nd[0]);

        int d = Integer.parseInt(nd[1]);

        int[] a = new int[n];

        String[] aItems = scanner.nextLine().split(" ");

        scanner.skip("(\r\n|[\n\r\u2028\u2029\u0085])?");

        for (int i = 0; i < n; i++) {

            int aItem = Integer.parseInt(aItems[i]);

            a[i] = aItem;

        }

        d=d%n;

        for(int i=d;i<n;i++)

        System.out.print(aItems[i]+" ");

        for(int i=0;i<d;i++)

        System.out.print(aItems[i]+" ");

        scanner.close();

    }

}